Difference between revisions of "Talk:2012 AMC 10A Problems/Problem 20"

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I get <math>\frac{49}{256}</math> for this problem.  I used your same logic, but noted that the center square can start out white or black, giving us: <math>\frac{2\cdot7\cdot7}{2^9}</math>.
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Latest revision as of 15:32, 12 February 2012