Difference between revisions of "1974 AHSME Problems/Problem 10"
(Created page with " ==Solution== Expanding, we have <math> 2kx^2-8x-x^2+6=0 </math>, or <math> (2k-1)x^2-8x+6=0 </math>. For this quadratic not to have real roots, it must have a negative discrimi...") |
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Revision as of 18:06, 26 May 2012
Solution
Expanding, we have , or
. For this quadratic not to have real roots, it must have a negative discriminant. Therefore,
. From here, we can easily see that the smallest integral value of
is
.