Difference between revisions of "User:Baijiangchen"

Latest revision as of 23:23, 21 July 2012

VOCOR·BENIAMINUM

If:

$W(0):=1$

$W(n):=\sum_{i=0}^{n-1}({n-1 \choose i}W(i)(x-i-1)!(2^{x-i-1}))$

Then:

$W(n)=(2n-1)!!$

Revision as of 23:22, 21 July 2012 (view source) Baijiangchen (talk \| contribs) (Created page with "If: <math>W(0):=1</math> <math>W(n):=\sum_{i=0}^{n-1}({n-1 \choose i}W(i)(x-i-1)!(2^{x-i-1}))</math> Then: <math>W(n)=(2n-1)!!</math>")		Latest revision as of 23:23, 21 July 2012 (view source) Baijiangchen (talk \| contribs)
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