Difference between revisions of "2013 AMC 12A Problems/Problem 10"
Epicwisdom (talk | contribs) (Created page with "Note that <math>\frac{1}{11} = 0.\overline{09}</math>. Dividing by 3 gives <math>\frac{1}{33} = 0.\overline{03}</math>, and dividing by 9 gives <math>\frac{1}{99} = 0.\overline{...") |
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Revision as of 23:05, 6 February 2013
Note that .
Dividing by 3 gives , and dividing by 9 gives
.
The answer must be at least , but cannot be
since no
other than
satisfies the conditions, so the answer is
.