Difference between revisions of "2013 AMC 10B Problems/Problem 4"

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==Problem==
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==Problem=
 
When counting from <math>3</math> to <math>201</math>, <math>53</math> is the <math>51^\mathrm{st}</math> number counted. When counting backwards from <math>201</math> to <math>3</math>, <math>53</math> is the <math>n^\mathrm{th}</math> number counted. What is <math>n</math>?
 
When counting from <math>3</math> to <math>201</math>, <math>53</math> is the <math>51^\mathrm{st}</math> number counted. When counting backwards from <math>201</math> to <math>3</math>, <math>53</math> is the <math>n^\mathrm{th}</math> number counted. What is <math>n</math>?
  

Revision as of 16:22, 21 February 2013

=Problem

When counting from $3$ to $201$, $53$ is the $51^\mathrm{st}$ number counted. When counting backwards from $201$ to $3$, $53$ is the $n^\mathrm{th}$ number counted. What is $n$?

$\textbf{(A)}\ 146\qquad\textbf{(B)}\ 147\qquad\textbf{(C)}\ 148\qquad\textbf{(D)}\ 149\qquad\textbf{(E)}\ 150$

Solution