|
|
| (3 intermediate revisions by 3 users not shown) |
| Line 1: |
Line 1: |
| − | ==Problem==
| + | #REDIRECT [[2013 AMC 12B Problems/Problem 1]] |
| − | | |
| − | On a particular January day, the high temperature in Lincoln, Nebraska, was 16 degrees higher than the low temperature, and the average of the high and the low temperatures was <math>3^\circ</math>. In degrees, what was the low temperature in Lincoln that day?
| |
| − | | |
| − | <math>\textbf{(A)}\ -13\qquad\textbf{(B)}\ -8\qquad\textbf{(C)}\ -5\qquad\textbf{(D)}\ -3\qquad\textbf{(E)}\ \ 11</math>
| |
| − | | |
| − | ==Solution==
| |
| − | | |
| − | Let <math>L</math> be the low temperature. The high temperature is <math>L+16</math>. The average is <math>\frac{L+(L+16)}{2}=3</math>. Solving for <math>L</math>, we get <math>L=\boxed{\textbf{(C) } -5}</math>
| |
