Difference between revisions of "1986 AJHSME Problems/Problem 15"

Revision as of 20:18, 3 July 2013

Problem

Sale prices at the Ajax Outlet Store are $50\%$ below original prices. On Saturdays an additional discount of $20\%$ off the sale price is given. What is the Saturday price of a coat whose original price is <dollar/> $180$ ?

$\text{(A)}$ <dollar/> $54$

$\text{(B)}$ <dollar/> $72$

$\text{(C)}$ <dollar/> $90$

$\text{(D)}$ <dollar/> $108$

$\text{(D)}$ <dollar/> $110$

Solution

First we need to do the first discount, which, at Ajax Outlet Store, would be there any day of the week. $\begin{align*} 180 \times 50\% &= 180 \times \frac{1}{2} \\ &= 90 \\ \end{align*}$

If we discount $20\%$ , then $80 \%$ will be left, so after the second discount, we get $\begin{align*} 90 \times 80\% &= 90 \times \frac{8}{10} \\ &= 9 \times 8 \\ &= 72 \\ \end{align*}$

$\boxed{\text{B}}$

1986 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 14	Followed by Problem 16
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 {{AJHSME box|year=1986|num-b=14|num-a=16}}
 [[Category:Introductory Algebra Problems]]
+{{MAA Notice}}

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Difference between revisions of "1986 AJHSME Problems/Problem 15"

Revision as of 20:18, 3 July 2013

Problem

Solution

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