Difference between revisions of "Power of a Point Theorem"
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== Introduction == | == Introduction == | ||
− | The Power of a Point | + | The '''Power of a Point Theorem''' expresses the relation between the lengths involved with the intersection of two lines between each other and their intersections with a [[circle]]. |
== Theorem == | == Theorem == | ||
Line 22: | Line 22: | ||
Notice how this definition still works if <math> A_k </math> and <math> B_k </math> coincide (as is the case with X). Consider also when P is inside the circle. The definition still holds in this case. | Notice how this definition still works if <math> A_k </math> and <math> B_k </math> coincide (as is the case with X). Consider also when P is inside the circle. The definition still holds in this case. | ||
+ | |||
+ | == Problems == | ||
+ | The problems are divided into three categories: introductory, intermediate, and olympiad. | ||
+ | |||
+ | === Introductory === | ||
+ | ==== Problem 1 ==== | ||
+ | Find the value of <math> x </math> in the following diagram: | ||
+ | |||
+ | <center>[[Image:popprob1.PNG]]</center> | ||
+ | |||
+ | [[Power of a Point Theorem Introductory Problem 1|Solution]] | ||
+ | |||
+ | ==== Problem 2 ==== | ||
+ | Find the value of <math> x </math> in the following diagram. | ||
+ | |||
+ | <center>[[Image:popprob2.PNG]]</center> | ||
+ | |||
+ | [[Power of a Point Theorem Introductory Problem 2|Solution]] | ||
+ | |||
+ | ==== Problem 3 ==== | ||
+ | ([[ARML]]) In a circle, chords <math> AB </math> and <math> CD </math> intersect at <math> R </math>. If <math>AR:BR = 1:4 </math> and <math> CR:DR = 4:9 </math>, find the ratio <math> AB:CD. </math> | ||
+ | |||
+ | <center>[[Image:popprob3.PNG]]</center> | ||
+ | |||
+ | [[Power of a Point Introductory Problem 3|Solution]] | ||
+ | |||
+ | ==== Problem 4 ==== | ||
+ | ([[ARML]]) Chords <math> AB </math> and <math> CD </math> of a given circle are perpendicular to each other and intersect at a right angle. Given that <math> BE = 16, DE = 4, </math> and <math> AD = 5 </math>, find <math> CE </math>. | ||
+ | |||
+ | [[Power of a Point Introductory Problem 4|Solution]] | ||
+ | |||
+ | {{problems}} | ||
==See also== | ==See also== | ||
* [[Geometry]] | * [[Geometry]] | ||
* [[Planar figures]] | * [[Planar figures]] |
Revision as of 22:18, 30 June 2006
Contents
[hide]Introduction
The Power of a Point Theorem expresses the relation between the lengths involved with the intersection of two lines between each other and their intersections with a circle.
Theorem
There are three possibilities as displayed in the figure below.
- The two lines are secants of the circle and intersect inside the circle (figure on the left). In this case, we have .
- One of the lines is tangent to the circle while the other is a secant (middle figure). In this case, we have .
- Both lines are secants of the circle and intersect outside of it (figure on the right). In this case, we have
Alternate Formulation
This alternate formulation is much more compact, convenient, and general.
Consider a circle O and a point P in the plane where P is not on the circle. Now draw a line through P that intersects the circle in two places. The power of a point theorem says that the product of the the length from P to the first point of intersection and the length from P to the second point of intersection is constant for any choice of a line through P that intersects the circle. This constant is called the power of point P. For example, in the figure below
Notice how this definition still works if and coincide (as is the case with X). Consider also when P is inside the circle. The definition still holds in this case.
Problems
The problems are divided into three categories: introductory, intermediate, and olympiad.
Introductory
Problem 1
Find the value of in the following diagram:
Problem 2
Find the value of in the following diagram.
Problem 3
(ARML) In a circle, chords and intersect at . If and , find the ratio
Problem 4
(ARML) Chords and of a given circle are perpendicular to each other and intersect at a right angle. Given that and , find .
This page is in need of some relevant examples or practice problems. Help us out by adding some. Thanks.