Difference between revisions of "2003 AMC 10B Problems/Problem 1"

Latest revision as of 23:02, 4 January 2014

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-==Problem==
+#REDIRECT [[2003 AMC 12B Problems/Problem 1]]
-Which of the following is the same as <math>\dfrac{2-4+6-8+10-12+14}{3-6+9-12+15-18+21}</math>?
-<math>\textbf{(A)}\ -1 \qquad
-\textbf{(B)}\ -\frac23 \qquad
-\textbf{(C)}\ \frac23 \qquad
-\textbf{(D)}\ 1 \qquad
-\textbf{(E)}\ \frac{14}{3}</math>
-==Solution==
-{{solution}}
-We can rewrite the given fraction as:
-<cmath>\frac{-3(2)+2(7)}{3(-3)+3(7)}=\frac{2(4)}{3(4)}=\frac{2}{3} \longrightarrow \boxed{\textbf{(C)}}</cmath>
-==See Also==
-{{AMC10 box|year=2003|ab=B|before=First Question|num-a=2}}
-[[Category: Introductory Algebra Problems]]