Difference between revisions of "1951 AHSME Problems/Problem 13"
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== Solution == | == Solution == | ||
| − | Because <math>B</math> is <math>50\%</math> more efficient, he can do <math>1.5</math> pieces of work in <math>9</math> days. This is equal to 1 piece of work in <math>\textbf{(C)}\ 6 </math> | + | Because <math>B</math> is <math>50\%</math> more efficient, he can do <math>1.5</math> pieces of work in <math>9</math> days. This is equal to 1 piece of work in <math>\textbf{(C)}\ 6 </math> days |
== See Also == | == See Also == | ||
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[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
| + | [[Category:Rate Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 16:07, 18 July 2015
Problem
can do a piece of work in 
days. 
is 
more efficient than . The number of days it takes to do the same piece of work is:
Solution
Because is more efficient, he can do 
pieces of work in days. This is equal to 1 piece of work in 
days
See Also
| 1951 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
