Difference between revisions of "1986 USAMO Problems"
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==Problem 1== | ==Problem 1== | ||
<math>(\text{a})</math> Do there exist 14 consecutive positive integers each of which is divisible by one or more primes <math>p</math> from the interval <math>2\le p \le 11</math>? | <math>(\text{a})</math> Do there exist 14 consecutive positive integers each of which is divisible by one or more primes <math>p</math> from the interval <math>2\le p \le 11</math>? |
Revision as of 13:44, 18 July 2016
Problems from the 1986 USAMO.
Problem 1
Do there exist 14 consecutive positive integers each of which is divisible by one or more primes from the interval ?
Do there exist 21 consecutive positive integers each of which is divisible by one or more primes from the interval ?
Problem 2
During a certain lecture, each of five mathematicians fell asleep exactly twice. For each pair of mathematicians, there was some moment when both were asleep simultaneously. Prove that, at some moment, three of them were sleeping simultaneously.
Problem 3
What is the smallest integer , greater than one, for which the root-mean-square of the first positive integers is an integer?
The root-mean-square of numbers is defined to be
Problem 4
Two distinct circles and are drawn in the plane. They intersect at points and , where is the diameter of . A point on and inside is also given.
Using only a "T-square" (i.e. an instrument which can produce a straight line joining two points and the perpendicular to a line through a point on or off the line), find a construction for two points and on such that is perpendicular to and is a right angle.
Problem 5
By a partition of an integer , we mean here a representation of as a sum of one or more positive integers where the summands must be put in nondecreasing order. (E.g., if , then the partitions are , , , and ).
For any partition , define to be the number of 's which appear in , and define to be the number of distinct integers which appear in . (E.g., if and is the partition , then and ).
Prove that, for any fixed , the sum of over all partitions of of is equal to the sum of over all partitions of of .
See Also
1986 USAMO (Problems • Resources) | ||
Preceded by 1985 USAMO |
Followed by 1987 USAMO | |
1 • 2 • 3 • 4 • 5 | ||
All USAMO Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.