Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "1987 USAMO Problems"

(→‎Problem 5)
m
 
(7 intermediate revisions by 3 users not shown)
Line 1: Line 1:
 +
Problems from the '''1987 [[USAMO]].'''
 +
 
==Problem 1==
 
==Problem 1==
 
Find all solutions to <math>(m^2+n)(m + n^2)= (m - n)^3</math>, where m and n are non-zero integers.
 
Find all solutions to <math>(m^2+n)(m + n^2)= (m - n)^3</math>, where m and n are non-zero integers.
Line 5: Line 7:
  
 
==Problem 2==
 
==Problem 2==
−
The feet of the angle bisectors of the triangle ABC form a right-angled triangle. If the right-angle is at X, where AX is the bisector of angle A, find all possible values for angle A.
+
The feet of the angle bisectors of <math>\Delta ABC</math> form a right-angled triangle. If the right-angle is at <math>X</math>, where <math>AX</math> is the bisector of <math>\angle A</math>, find all possible values for <math>\angle A</math>.
  
−
[[1987USAMO Problems/Problem 2|Solution]]
+
[[1987 USAMO Problems/Problem 2|Solution]]
  
 
==Problem 3==
 
==Problem 3==
−
X is the smallest set of polynomials <math>p(x)</math> such that:  
+
<math>X</math> is the smallest set of polynomials <math>p(x)</math> such that:  
  
−
1. <math>p(x) = x</math> belongs to X
+
: 1. <math>p(x) = x</math> belongs to <math>X</math>.
−
2. If <math>r(x)</math> belongs to X, then <math>x\cdot r(x)</math> and <math>(x + (1 - x) \cdot r(x) )</math> both belong to X.  
+
: 2. If <math>r(x)</math> belongs to <math>X</math>, then <math>x\cdot r(x)</math> and <math>(x + (1 - x) \cdot r(x) )</math> both belong to <math>X</math>.  
  
−
Show that if <math>r(x)</math> and <math>s(x)</math> are distinct elements of X, then <math>r(x) \neq s(x)</math> for any <math>0 < x < 1</math>.  
+
Show that if <math>r(x)</math> and <math>s(x)</math> are distinct elements of <math>X</math>, then <math>r(x) \neq s(x)</math> for any <math>0 < x < 1</math>.  
  
−
[[1987USAMO Problems/Problem 3|Solution]]
+
[[1987 USAMO Problems/Problem 3|Solution]]
  
 
==Problem 4==
 
==Problem 4==
 
M is the midpoint of XY. The points P and Q lie on a line through Y on opposite sides of Y, such that <math>|XQ| = 2|MP|</math> and <math>\frac{|XY|}2 < |MP| < \frac{3|XY|}2</math>. For what value of <math>\frac{|PY|}{|QY|}</math> is <math>|PQ|</math> a minimum?  
 
M is the midpoint of XY. The points P and Q lie on a line through Y on opposite sides of Y, such that <math>|XQ| = 2|MP|</math> and <math>\frac{|XY|}2 < |MP| < \frac{3|XY|}2</math>. For what value of <math>\frac{|PY|}{|QY|}</math> is <math>|PQ|</math> a minimum?  
  
−
[[1987USAMO Problems/Problem 4|Solution]]
+
[[1987 USAMO Problems/Problem 4|Solution]]
  
 
==Problem 5==
 
==Problem 5==
 
<math>a_1, a_2, \cdots, a_n</math> is a sequence of 0's and 1's. T is the number of triples <math>(a_i, a_j, a_k)</math> with <math>i<j<k</math> which are not equal to (0, 1, 0) or (1, 0, 1). For <math>1\le i\le n</math>, <math>f(i)</math> is the number of <math>j<i</math> with <math>a_j = a_i</math> plus the number of <math>j>i</math> with <math>a_j\neq a_i</math>. Show that <math>T=\sum_{i=1}^n f(i)\cdot\left(\frac{f(i)-1}2\right)</math>. If n is odd, what is the smallest value of T?
 
<math>a_1, a_2, \cdots, a_n</math> is a sequence of 0's and 1's. T is the number of triples <math>(a_i, a_j, a_k)</math> with <math>i<j<k</math> which are not equal to (0, 1, 0) or (1, 0, 1). For <math>1\le i\le n</math>, <math>f(i)</math> is the number of <math>j<i</math> with <math>a_j = a_i</math> plus the number of <math>j>i</math> with <math>a_j\neq a_i</math>. Show that <math>T=\sum_{i=1}^n f(i)\cdot\left(\frac{f(i)-1}2\right)</math>. If n is odd, what is the smallest value of T?
  
−
[[1987USAMO Problems/Problem 5|Solution]]
+
[[1987 USAMO Problems/Problem 5|Solution]]
 +
 
 +
== See Also ==
 +
{{USAMO box|year=1987|before=[[1986 USAMO]]|after=[[1988 USAMO]]}}
 +
{{MAA Notice}}

Latest revision as of 17:42, 18 July 2016

Problems from the 1987 USAMO.

Problem 1

Find all solutions to $(m^2+n)(m + n^2)= (m - n)^3$, where m and n are non-zero integers.

Solution

Problem 2

The feet of the angle bisectors of $\Delta ABC$ form a right-angled triangle. If the right-angle is at $X$, where $AX$ is the bisector of $\angle A$, find all possible values for $\angle A$.

Solution

Problem 3

$X$ is the smallest set of polynomials $p(x)$ such that:

1. $p(x) = x$ belongs to $X$.
2. If $r(x)$ belongs to $X$, then $x\cdot r(x)$ and $(x + (1 - x) \cdot r(x) )$ both belong to $X$.

Show that if $r(x)$ and $s(x)$ are distinct elements of $X$, then $r(x) \neq s(x)$ for any $0 < x < 1$.

Solution

Problem 4

M is the midpoint of XY. The points P and Q lie on a line through Y on opposite sides of Y, such that $|XQ| = 2|MP|$ and $\frac{|XY|}2 < |MP| < \frac{3|XY|}2$. For what value of $\frac{|PY|}{|QY|}$ is $|PQ|$ a minimum?

Solution

Problem 5

$a_1, a_2, \cdots, a_n$ is a sequence of 0's and 1's. T is the number of triples $(a_i, a_j, a_k)$ with $i<j<k$ which are not equal to (0, 1, 0) or (1, 0, 1). For $1\le i\le n$, $f(i)$ is the number of $j<i$ with $a_j = a_i$ plus the number of $j>i$ with $a_j\neq a_i$. Show that $T=\sum_{i=1}^n f(i)\cdot\left(\frac{f(i)-1}2\right)$. If n is odd, what is the smallest value of T?

Solution

See Also

1987 USAMO (Problems • Resources)
Preceded by
1986 USAMO 		Followed by
1988 USAMO
1 • 2 • 3 • 4 • 5
All USAMO Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=1987_USAMO_Problems&oldid=79434"