Difference between revisions of "1996 USAMO Problems/Problem 3"
(Reconstructed from page template) |
m (→See Also) |
||
| Line 6: | Line 6: | ||
== See Also == | == See Also == | ||
| − | {{USAMO | + | {{USAMO newbox|year=1996|num-b=2|num-a=4}} |
{{MAA Notice}} | {{MAA Notice}} | ||
[[Category:Olympiad Geometry Problems]] | [[Category:Olympiad Geometry Problems]] | ||
Revision as of 08:28, 20 July 2016
Problem
Let 
be a triangle. Prove that there is a line 
(in the plane of triangle ) such that the intersection of the interior of triangle and the interior of its reflection 
in has area more than 
the area of triangle .
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See Also
| 1996 USAMO (Problems • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 | ||
| All USAMO Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
