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Difference between revisions of "1977 AHSME Problems/Problem 8"

(Created page with "==Solution== Solution by e_power_pi_times_i <math>\dfrac{x}{|x} = 1</math> or <math>-1</math> depending whether <math>x</math> is positive or negative. If <math>a</math>, <ma...")
(No difference)

Revision as of 12:17, 18 November 2016

Solution

Solution by e_power_pi_times_i

$\dfrac{x}{|x} = 1$ or $-1$ depending whether $x$ is positive or negative. If $a$, $b$, and $c$ are positive, then the entire thing amounts to $4$. If one of the three is negative and the other two positive, the answer is $0$. If two of the three is negative and one is positive, the answer is $0$. If all three are negative, the answer is $-4$. Therefore the set is $\boxed{\textbf{(B)}\ \{-4,0,4\}}$.

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