Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 27"
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Notice that <math>P</math> is the [[incenter]] of the [[triangle]]. The [[incircle]] has [[radius]] <math>2</math>. Thus, using <math>rs=A</math>, we have <math>2 \cdot s=24 \Longrightarrow s=12</math> and the perimeter is <math>24</math>. | Notice that <math>P</math> is the [[incenter]] of the [[triangle]]. The [[incircle]] has [[radius]] <math>2</math>. Thus, using <math>rs=A</math>, we have <math>2 \cdot s=24 \Longrightarrow s=12</math> and the perimeter is <math>24</math>. | ||
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− | * [[University of South Carolina High School Math Contest/1993 Exam]] | + | |
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+ | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 28/Next Problem]] | ||
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[[Category:Intermediate Geometry Problems]] | [[Category:Intermediate Geometry Problems]] |