Difference between revisions of "Mock AIME I 2015 Problems/Problem 2"
m |
Blunderbro (talk | contribs) (→Original Solution) |
||
(One intermediate revision by the same user not shown) | |||
Line 28: | Line 28: | ||
By rearranging the values, it is possible to attain an | By rearranging the values, it is possible to attain an | ||
− | x= 3^ | + | <math>x= 3^ {65/17}</math> |
and | and | ||
− | y= 3^ | + | <math>y= 3^ {33/17}</math> |
Therefore, a/b is equal to 25/61, so 25+41= 061 | Therefore, a/b is equal to 25/61, so 25+41= 061 | ||
+ | |||
+ | Ignore the original solution as it is incorrect - blunderbro | ||
+ | Solution at the top checked by blunderbro | ||
+ | Note: It is correct, original one was the first one posted but was incorrect. |
Latest revision as of 03:24, 9 January 2017
Problem
Suppose that and
are real numbers such that
and
. The value of
can be expressed in the form
where
and
are positive relatively prime integers. Find
.
Corrected Solution and Answer
Use the logarithmic identity to expand the assumptions to
and
Solve for the values of and
which are respectively
and
The sought ratio is
The answer then is
Solution by D. Adrian Tanner (Original solution and answer below)
Original Solution
By rearranging the values, it is possible to attain an
and
Therefore, a/b is equal to 25/61, so 25+41= 061
Ignore the original solution as it is incorrect - blunderbro Solution at the top checked by blunderbro Note: It is correct, original one was the first one posted but was incorrect.