Difference between revisions of "Vieta's Formulas"
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Expanding out the right hand side gives us | Expanding out the right hand side gives us | ||
− | <math> | + | <math> a_nx^n - a_n(r_1+r_2+\!\cdots\!+r_n)x^{n-1} + a_n(r_1r_2 + r_1r_3 +\! \cdots\! + r_{n-1}r_n)x^{n-2} +\! \cdots\! + (-1)^na_n r_1r_2\cdots r_n.</math> |
The coefficient of <math>\displaystyle x^k </math> in this expression will be the <math> \displaystyle k </math>th [[symmetric sum]] of the <math>r_i</math>. | The coefficient of <math>\displaystyle x^k </math> in this expression will be the <math> \displaystyle k </math>th [[symmetric sum]] of the <math>r_i</math>. |
Revision as of 22:14, 24 July 2006
Vieta's formulas are a set of equations relating the roots and the coefficients of polynomials.
Introduction
Let be a polynomial of degree
, so
,
where the coefficient of
is
and
. As a consequence of the Fundamental Theorem of Algebra, we can also write
, where
are the roots of
. We thus have that
![$a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0 = a_n(x-r_1)(x-r_2)\cdots(x-r_n).$](http://latex.artofproblemsolving.com/4/4/b/44b0375f3fff54d4440ac27ed32a29ea26fa6f10.png)
Expanding out the right hand side gives us
The coefficient of in this expression will be the
th symmetric sum of the
.
We now have two different expressions for . These must be equal. However, the only way for two polynomials to be equal for all values of
is for each of their corresponding coefficients to be equal. So, starting with the coefficient of
, we see that
![$\displaystyle a_n = a_n$](http://latex.artofproblemsolving.com/d/a/d/dad5b455e9395f5d6d9525cbb35600d36028fb8a.png)
![$a_{n-1} = -a_n(r_1+r_2+\cdots+r_n)$](http://latex.artofproblemsolving.com/e/9/8/e98bba0737992471e152a486d4e12fc9d38f8803.png)
![$a_{n-2} = a_n(r_1r_2+r_1r_3+\cdots+r_{n-1}r_n)$](http://latex.artofproblemsolving.com/e/5/7/e5734e66af5754c9f39706aafe68f3a0eb2bff8c.png)
![$\vdots$](http://latex.artofproblemsolving.com/6/9/c/69cdf7ec84ff918cbe7f21acf7543bf1bd243080.png)
![$a_0 = (-1)^n a_n r_1r_2\cdots r_n$](http://latex.artofproblemsolving.com/1/3/f/13f11a26327cb547c656475c515683b949d4823a.png)
More commonly, these are written with the roots on one side and the on the other (this can be arrived at by dividing both sides of all the equations by
).
If we denote as the
th symmetric sum, then we can write those formulas more compactly as
, for
.