Difference between revisions of "2006 AMC 8 Problems/Problem 11"
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Thus, the answer is <math> 1 + 4 + 9 + 3 = \boxed{\textbf{(C)} 17} </math>. | Thus, the answer is <math> 1 + 4 + 9 + 3 = \boxed{\textbf{(C)} 17} </math>. | ||
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Revision as of 22:52, 5 May 2017
Problem
How many two-digit numbers have digits whose sum is a perfect square?
Solution
There is integer whose digits sum to : .
There are integers whose digits sum to : .
There are integers whose digits sum to : .
There are integers whose digits sum to : .
Two digits cannot sum to or any greater square since the greatest sum of digits of a two-digit number is .
Thus, the answer is .