Difference between revisions of "1955 AHSME Problems/Problem 4"
Awesomechoco (talk | contribs) (→Solution) |
Awesomechoco (talk | contribs) (→Solution) |
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Solving this, we get, <math>{2x-2}={x-2}</math>. | Solving this, we get, <math>{2x-2}={x-2}</math>. | ||
− | Thus, {only x=0 | + | Thus, \ \text{only }x=0$ can satisfy the equation, {(E)}. |
Revision as of 22:57, 6 July 2018
Problem
The equality is satisfied by:
Solution
From the equality, , we get .
Solving this, we get, .
Thus, \ \text{only }x=0$ can satisfy the equation, {(E)}.