Difference between revisions of "1971 AHSME Problems/Problem 1"
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== Solution == | == Solution == | ||
− | <math>N=2^{12}\cdot5^8=2^4\cdot2^8\cdot5^8=2^4\cdot(2\cdot5)^8=2^4\cdot10^8=16\cdot100000000</math>, which has <math>2+8=10</math> digits, so the answer is <math>(\textbf{ | + | <math>N=2^{12}\cdot5^8=2^4\cdot2^8\cdot5^8=2^4\cdot(2\cdot5)^8=2^4\cdot10^8=16\cdot100000000</math>, which has <math>2+8=10</math> digits, so the answer is <math>(\textbf{B})</math>. |
Revision as of 02:49, 13 July 2018
Problem 1
The number of digits in the number is
Solution
, which has
digits, so the answer is
.