Difference between revisions of "1994 AHSME Problems/Problem 30"
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<math> \textbf{(A)}\ 333 \qquad\textbf{(B)}\ 335 \qquad\textbf{(C)}\ 337 \qquad\textbf{(D)}\ 339 \qquad\textbf{(E)}\ 341 </math> | <math> \textbf{(A)}\ 333 \qquad\textbf{(B)}\ 335 \qquad\textbf{(C)}\ 337 \qquad\textbf{(D)}\ 339 \qquad\textbf{(E)}\ 341 </math> | ||
==Solution== | ==Solution== | ||
− | Since the sum of dice is <math>1994</math>, there are at least <math>333</math> | + | Since the sum of dice is <math>1994</math>, there are at least <math>333</math> dices. Now consider the following numbers <math>\underbrace { 6+6+ \dots + 6 }_{ 332 } + 2</math> and <math>\underbrace{ 1+1+ \dots + 1 }_{ 332 } + 5</math>. They both have the same probability of occurring because <math>6</math> negated by switching it to <math>1</math> and <math>2</math> is negated by switching it to <math>5</math>. So we have obtained an upper bound over <math>S</math> which is <math>1 \cdot 332 + 5 = 337</math>. Only smaller numbers to consider are <math>1 \cdot 332 + 4</math>, <math>1 \cdot 332 + 3</math>, <math>1 \cdot 332 + 2</math>, <math>1 \cdot 332 + 1</math>. As it turns out, none of these work. |
Revision as of 23:09, 30 July 2018
Problem
When standard 6-sided dice are rolled, the probability of obtaining a sum of 1994 is greater than zero and is the same as the probability of obtaining a sum of . The smallest possible value of is
Solution
Since the sum of dice is , there are at least dices. Now consider the following numbers and . They both have the same probability of occurring because negated by switching it to and is negated by switching it to . So we have obtained an upper bound over which is . Only smaller numbers to consider are , , , . As it turns out, none of these work.