Difference between revisions of "1959 AHSME Problems/Problem 11"

(Created page with "==Solution== <cmath>\log_{2}{0.625}=\log_{2}{\frac{1}{16}}=\boxed{-4}.</cmath>")
 
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Latest revision as of 06:08, 24 September 2018

Solution

\[\log_{2}{0.625}=\log_{2}{\frac{1}{16}}=\boxed{-4}.\]