Difference between revisions of "2018 UNM-PNM Statewide High School Mathematics Contest II Problems/Problem 4"
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Let any one side be x and other side be y. | Let any one side be x and other side be y. | ||
− | Then one diagonal is <math> | + | Then one diagonal is <math>\sqrt{y^{2} - x^{2}}</math> |
− | let | + | let <math>\sqrt{y^{2} - x^{2}}</math> be z. |
− | So x* | + | So x* <math>\sqrt{y^{2} - x^{2}}</math> = <math>39\sqrt{95}</math> |
Here x = 13 satisfies with y = 32 { By Hit And Trial Method } | Here x = 13 satisfies with y = 32 { By Hit And Trial Method } | ||
− | so Perimeter is 2(13+32) | + | so Perimeter is 2(13+32) <math>\Rightarrow{\boxed {90}}</math> |
== See also == | == See also == |
Latest revision as of 06:39, 9 August 2019
Problem
Suppose ABCD is a parallelogram with area square units and is a right angle. If the lengths of all the sides of ABCD are integers, what is the perimeter of ABCD?
Solution
(Involves Hit and Trial) Let any one side be x and other side be y.
Then one diagonal is
let be z.
So x* =
Here x = 13 satisfies with y = 32 { By Hit And Trial Method }
so Perimeter is 2(13+32)
See also
2018 UNM-PNM Contest II (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNM-PNM Problems and Solutions |