Difference between revisions of "2013 AMC 10A Problems/Problem 1"
m (→Problem) |
(→Video Solution) |
||
(One intermediate revision by one other user not shown) | |||
Line 9: | Line 9: | ||
There are five miles which need to be traveled. The cost of these five miles is <math>(0.25\cdot5) = 1.25</math>. Adding this to <math>1.50</math>, we get <math>\boxed{\textbf{(C) }2.75}</math> | There are five miles which need to be traveled. The cost of these five miles is <math>(0.25\cdot5) = 1.25</math>. Adding this to <math>1.50</math>, we get <math>\boxed{\textbf{(C) }2.75}</math> | ||
+ | ==Video Solution (CREATIVE THINKING)== | ||
+ | https://youtu.be/4XDyloZUY48 | ||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/hIklCIgfxcg | ||
+ | |||
+ | ~savannahsolver | ||
==See Also== | ==See Also== |
Latest revision as of 12:11, 1 July 2023
Contents
[hide]Problem
A taxi ride costs plus per mile traveled. How much does a -mile taxi ride cost?
Solution
There are five miles which need to be traveled. The cost of these five miles is . Adding this to , we get
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2013 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.