Difference between revisions of "2019 CIME I Problems/Problem 13"

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Suppose <math>\text{P}</math> is a monic polynomial whose roots <math>a</math>, <math>b</math>, and <math>c</math> are real numbers, at least two of which are positive, that satisfy the relation <cmath>a(a-b)=b(b-c)=c(c-a)=1.</cmath> Find the greatest integer less than or equal to <math>100|P(\sqrt{3})|</math>.
 
Suppose <math>\text{P}</math> is a monic polynomial whose roots <math>a</math>, <math>b</math>, and <math>c</math> are real numbers, at least two of which are positive, that satisfy the relation <cmath>a(a-b)=b(b-c)=c(c-a)=1.</cmath> Find the greatest integer less than or equal to <math>100|P(\sqrt{3})|</math>.
  
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==Solution==
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Don't ask how, but it's 981.
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==See also==
 
{{CIME box|year=2019|n=I|num-b=12|num-a=14}}
 
{{CIME box|year=2019|n=I|num-b=12|num-a=14}}
  
 
[[Category:Intermediate Algebra Problems]]
 
[[Category:Intermediate Algebra Problems]]
 
{{MAC Notice}}
 
{{MAC Notice}}

Latest revision as of 01:23, 8 March 2024

Suppose $\text{P}$ is a monic polynomial whose roots $a$, $b$, and $c$ are real numbers, at least two of which are positive, that satisfy the relation \[a(a-b)=b(b-c)=c(c-a)=1.\] Find the greatest integer less than or equal to $100|P(\sqrt{3})|$.

Solution

Don't ask how, but it's 981.

See also

2019 CIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All CIME Problems and Solutions

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