Difference between revisions of "1963 TMTA High School Algebra I Contest Problem 8"
Coolmath34 (talk | contribs) (Created page with "== Problem == <math>\frac{a^(-1) + b^(-1)}{(a+b)^(-1)}</math> is equal to <math>\text{(A)} \quad K-10 \quad \text{(B)} \quad 5K-20 \quad \text{(C)} \quad \frac{K-4}{5} \quad...") |
Coolmath34 (talk | contribs) |
||
Line 1: | Line 1: | ||
== Problem == | == Problem == | ||
− | <math>\frac{a^ | + | <math>\frac{a^{-1} + b^{-1}}{(a+b)^{-1}}</math> is equal to |
− | <math>\text{(A)} \quad | + | <math>\text{(A)} \quad \frac{(a+b)^2}{ab} \quad \text{(B)} \quad \frac{1}{ab} \quad \text{(C)} \quad ab \quad \text{(D)} \quad \frac{ab}{(a+b)^2} \quad \text{(E)} a+b</math> |
== Solution == | == Solution == | ||
− | + | <math>\frac{\frac{1}{a} + \frac{1}{b}}{\frac{1}{a+b}} = \frac{\frac{a+b}{ab}}{\frac{1}{a+b}} = \frac{a+b}{ab} \cdot (a+b) = \boxed{\text{(A)} \quad \frac{(a+b)^2}{ab}}</math> | |
− | <math>( | ||
− | |||
== See Also == | == See Also == | ||
{{Succession box | {{Succession box |
Latest revision as of 22:55, 1 February 2021
Problem
is equal to
Solution
See Also
1963 TMTA High School Mathematics Contests (Problems) | ||
Preceded by Problem 7 |
TMTA High School Mathematics Contest Past Problems/Solutions | Followed by Problem 9 |