Difference between revisions of "G285 MC10B Problems/Problem 1"
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==Solution== | ==Solution== | ||
− | We have <cmath>\frac{6+24+120+720}{20} = \frac{87}{2} = \ | + | We have <cmath>\frac{6+24+120+720}{20} = \frac{87}{2} = \lceil 43.5 \rceil \implies \boxed{\textbf{(C)}\ 44}</cmath> |
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Latest revision as of 22:57, 3 June 2022
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