Difference between revisions of "2021 JMPSC Sprint Problems/Problem 6"
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==Solution== | ==Solution== | ||
− | + | The probability in which a random choosing of a coin from a pool of <math>100</math> coins bringing out a nickel is <math>\frac{2}{5}</math>. Multiplying the fraction by <math>\frac{20}{20}</math>, we get <math>\frac{40}{100}</math>, or <math>40</math> coins out of <math>100</math>. This means that there are <math>40</math> nickels, and <math>60</math> dimes. | |
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+ | The value of <math>40</math> nickels is: <math>40\cdot 0.05=2.00</math>, or two dollars. | ||
+ | On the other hand, the value of <math>60</math> dimes is: <math>60 \cdot 0.10=6.00</math>, or <math>6</math> dollars. | ||
+ | |||
+ | Therefore, Luis has a total of <math>6+2</math> <math>=</math> <math>\boxed{8}</math> dollars total in dimes and nickels. | ||
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+ | -OofPirate | ||
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+ | ==See also== | ||
+ | #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] | ||
+ | #[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]] | ||
+ | #[[JMPSC Problems and Solutions|All JMPSC Problems and Solutions]] | ||
+ | {{JMPSC Notice}} |
Latest revision as of 17:13, 11 July 2021
Problem
Luis has coins that are all either nickels or dimes. If the probability of randomly picking a nickel from these
coins is
how much money does Luis have in dollars?
Solution
The probability in which a random choosing of a coin from a pool of coins bringing out a nickel is
. Multiplying the fraction by
, we get
, or
coins out of
. This means that there are
nickels, and
dimes.
The value of nickels is:
, or two dollars.
On the other hand, the value of
dimes is:
, or
dollars.
Therefore, Luis has a total of
dollars total in dimes and nickels.
-OofPirate
See also
The problems on this page are copyrighted by the Junior Mathematicians' Problem Solving Competition.