Difference between revisions of "2006 AMC 8 Problems/Problem 7"
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== Solution == | == Solution == | ||
− | Using the formulas of circles, <math> C=2 \pi r </math> and <math> A= \pi r^2 </math>, we find that circle <math> Y </math> has a radius of <math> 4 </math> and circle <math> Z </math> has a radius of <math> 3 </math>. Thus, the order from smallest to largest radius is <math> \boxed{\textbf{(B)}\ Z, X, Y} </math>. | + | Using the formulas of circles, <math> C=2 \pi r </math> and <math> A= \pi r^2 </math>, we find that circle <math> Y </math> has a radius of <math> 4 </math> and circle <math> Z </math> has a radius of <math> 3 </math>. Also, circle X has a radius of <math> \pi </math>. Thus, the order from smallest to largest radius is <math> \boxed{\textbf{(B)}\ Z, X, Y} </math>. |
+ | |||
+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/J5-hDWd28tM | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|num-b=6|num-a=8}} | {{AMC8 box|year=2006|num-b=6|num-a=8}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 13:21, 29 October 2024
Problem 7
Circle has a radius of . Circle has a circumference of . Circle has an area of . List the circles in order from smallest to the largest radius.
Solution
Using the formulas of circles, and , we find that circle has a radius of and circle has a radius of . Also, circle X has a radius of . Thus, the order from smallest to largest radius is .
Video Solution by WhyMath
See Also
2006 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 6 |
Followed by Problem 8 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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