Difference between revisions of "2023 AMC 10A Problems/Problem 9"

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==Problem==
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#redirect[[2023 AMC 12A Problems/Problem 7]]
A digital display shows the current date as an <math>8</math>-digit integer consisting of a <math>4</math>-digit year, followed by a <math>2</math>-digit month, followed by a <math>2</math>-digit date within the month. For example, Arbor Day this year is displayed as 20230428. For how many dates in <math>2023</math> will each digit appear an even number of times in the 8-digital display for that date?
 
 
 
<math>\textbf{(A)}~5\qquad\textbf{(B)}~6\qquad\textbf{(C)}~7\qquad\textbf{(D)}~8\qquad\textbf{(E)}~9</math>
 
 
 
==Solution==
 
Do careful casework by each month. In the month and the date, we need a <math>0</math>, a <math>3</math>, and two digits repeated. After the case work, we get <math>9</math>, meaning the answer <math>\boxed{\textbf{(E)}~9}</math>.
 
For those who are wondering, the numbers are:
 
20230113, 20230131, 20230223, 20230311, 20230322, 20231013, 20231031, 20231103, 20231130.
 
 
 
== Video Solution 1 by OmegaLearn ==
 
https://youtu.be/xguAy0PV7EA
 
 
 
==See Also==
 
{{AMC10 box|year=2023|ab=A|num-b=8|num-a=10}}
 
{{MAA Notice}}
 

Latest revision as of 22:25, 9 November 2023