Difference between revisions of "1987 OIM Problems/Problem 2"

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== Problem ==
 
== Problem ==
 
On a triangle <math>ABC</math>, <math>M</math> and <math>N</math> are the respective midpoints of sides <math>AC</math> and <math>AB</math>, and <math>P</math> is the midpoint of the intersection of <math>BM</math> and <math>CN</math>.  Prove that, if is possible to inscribe a circumference in the quadrilateral <math>ANPM</math>, then triangle <math>ABC</math> is isosceles.
 
On a triangle <math>ABC</math>, <math>M</math> and <math>N</math> are the respective midpoints of sides <math>AC</math> and <math>AB</math>, and <math>P</math> is the midpoint of the intersection of <math>BM</math> and <math>CN</math>.  Prove that, if is possible to inscribe a circumference in the quadrilateral <math>ANPM</math>, then triangle <math>ABC</math> is isosceles.
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~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
  
 
== Solution ==
 
== Solution ==
 
{{solution}}
 
{{solution}}
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== See also ==
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https://www.oma.org.ar/enunciados/ibe2.htm

Latest revision as of 12:26, 13 December 2023

Problem

On a triangle $ABC$, $M$ and $N$ are the respective midpoints of sides $AC$ and $AB$, and $P$ is the midpoint of the intersection of $BM$ and $CN$. Prove that, if is possible to inscribe a circumference in the quadrilateral $ANPM$, then triangle $ABC$ is isosceles.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe2.htm