Difference between revisions of "1988 OIM Problems/Problem 4"
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== Problem == | == Problem == | ||
Let <math>ABC</math> be a triangle which sides are <math>a</math>, <math>b</math>, <math>c</math>. We divide each side of the triangle in <math>n</math> equal segments. Let <math>S</math> be the sum of the squares of the distances from each vertex to each of the points dividing the opposite side different from the vertices. | Let <math>ABC</math> be a triangle which sides are <math>a</math>, <math>b</math>, <math>c</math>. We divide each side of the triangle in <math>n</math> equal segments. Let <math>S</math> be the sum of the squares of the distances from each vertex to each of the points dividing the opposite side different from the vertices. | ||
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Prove that <math>\frac{S}{a^2+b^2+c^2}</math> is rational. | Prove that <math>\frac{S}{a^2+b^2+c^2}</math> is rational. | ||
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| + | ~translated into English by Tomas Diaz. ~orders@tomasdiaz.com | ||
== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
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| + | == See also == | ||
| + | https://www.oma.org.ar/enunciados/ibe3.htm | ||
Latest revision as of 13:28, 13 December 2023
Problem
Let 
be a triangle which sides are 
, 
, 
. We divide each side of the triangle in 
equal segments. Let 
be the sum of the squares of the distances from each vertex to each of the points dividing the opposite side different from the vertices.
Prove that 
is rational.
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
Solution
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