Difference between revisions of "2025 AMC 8 Problems"

Latest revision as of 10:28, 31 July 2024

The 2025 AMC 8 is not held yet. Please do not post false problems.

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-<math>1)</math> Let <math>m</math> and <math>n</math> be <math>2</math> integers such that <math>m>n</math>. Suppose <math>m+n=20</math>, <math>m^2+n^2=328</math>, find <math>m^2-n^2</math>.
+The 2025 AMC 8 is not held yet. '''Please do not post false problems.'''
-<math>\textbf{(A)}\ 280 \qquad \textbf{(B)}\ 292 \qquad \textbf{(C)}\ 300 \qquad \textbf{(D)}\ 320 \qquad \textbf{(E)}\ 340</math>
-<math>2)</math>