Difference between revisions of "2024 AMC 8 Problems/Problem 6"
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You can measure the lengths of the paths until you find a couple of guaranteed true inferred statements as such: | You can measure the lengths of the paths until you find a couple of guaranteed true inferred statements as such: | ||
| − | Q is greater than S, | + | <math>Q</math> is greater than <math>S</math>, |
| − | P is greater than R, | + | <math>P</math> is greater than <math>R</math>, |
| − | and R and P are the smallest two, therefore the order is R, P, S, Q. | + | and <math>R</math> and <math>P</math> are the smallest two, therefore the order is <math>R, P, S, Q.</math> |
Thus we get the answer <math>\boxed{\textbf{(D)}~R, P, S, Q}</math>. | Thus we get the answer <math>\boxed{\textbf{(D)}~R, P, S, Q}</math>. | ||
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~ cxsmi (minor <math>\LaTeX</math> edits) | ~ cxsmi (minor <math>\LaTeX</math> edits) | ||
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| + | ~TabHawaii (minor formatting edits) | ||
==Solution 2 (Intuitive)== | ==Solution 2 (Intuitive)== | ||
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~MrThinker | ~MrThinker | ||
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==Video Solution by Math-X (First fully understand the problem!!!)== | ==Video Solution by Math-X (First fully understand the problem!!!)== | ||
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==Video Solution by Power Solve (easy to digest!)== | ==Video Solution by Power Solve (easy to digest!)== | ||
https://www.youtube.com/watch?v=16YYti_pDUg | https://www.youtube.com/watch?v=16YYti_pDUg | ||
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| + | ==Video Solution (A Clever Explanation You’ll Get Instantly)== | ||
| + | https://youtu.be/5ZIFnqymdDQ?si=MmMWctYfzKIjwfE8&t=553 | ||
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| + | ~hsnacademy | ||
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| + | ==Video Solution 1 by NiuniuMaths (Easy to understand!)== | ||
| + | https://www.youtube.com/watch?v=V-xN8Njd_Lc | ||
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| + | ~NiuniuMaths | ||
==Video Solution by Interstigation== | ==Video Solution by Interstigation== | ||
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~Thesmartgreekmathdude | ~Thesmartgreekmathdude | ||
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| + | ==Video Solution by WhyMath== | ||
| + | https://youtu.be/mMDp6k_C6MI | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2024|num-b=5|num-a=7}} | {{AMC8 box|year=2024|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 15:50, 20 November 2024
Contents
- 1 Problem
- 2 Solution 1
- 3 Solution 2 (Intuitive)
- 4 Video Solution by Math-X (First fully understand the problem!!!)
- 5 Video Solution by Power Solve (easy to digest!)
- 6 Video Solution (A Clever Explanation You’ll Get Instantly)
- 7 Video Solution 1 by NiuniuMaths (Easy to understand!)
- 8 Video Solution by Interstigation
- 9 Video Solution by Daily Dose of Math (Certified, Simple, and Logical)
- 10 Video Solution by WhyMath
- 11 See Also
Problem
Sergai skated around an ice rink, gliding along different paths. The gray lines in the figures below show four of the paths labeled P, Q, R, and S. What is the sorted order of the four paths from shortest to longest?
Solution 1
You can measure the lengths of the paths until you find a couple of guaranteed true inferred statements as such:
is greater than 
,
is greater than 
,
and and are the smallest two, therefore the order is 
Thus we get the answer 
.
- U-King
~ cxsmi (minor 
edits)
~TabHawaii (minor formatting edits)
Solution 2 (Intuitive)
Obviously Path Q is the longest path, followed by Path S.
So, it is down to Paths P and R.
Notice that curved lines are always longer than the straight ones that meet their endpoints, therefore Path P is longer than Path R.
Thus, the order from shortest to longest is 
.
~MrThinker
Video Solution by Math-X (First fully understand the problem!!!)
https://youtu.be/BaE00H2SHQM?si=ZedvqIYTDG3D20Rp&t=1301
~Math-X
Video Solution by Power Solve (easy to digest!)
https://www.youtube.com/watch?v=16YYti_pDUg
Video Solution (A Clever Explanation You’ll Get Instantly)
https://youtu.be/5ZIFnqymdDQ?si=MmMWctYfzKIjwfE8&t=553
~hsnacademy
Video Solution 1 by NiuniuMaths (Easy to understand!)
https://www.youtube.com/watch?v=V-xN8Njd_Lc
~NiuniuMaths
Video Solution by Interstigation
https://youtu.be/ktzijuZtDas&t=386
Video Solution by Daily Dose of Math (Certified, Simple, and Logical)
~Thesmartgreekmathdude
Video Solution by WhyMath
See Also
| 2024 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
