Difference between revisions of "2024 AMC 8 Problems/Problem 2"

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<math>4+2.5+0.04</math> reveals <cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath> is <math>\boxed{\text{(C)\ 6.54}}</math>.  
 
<math>4+2.5+0.04</math> reveals <cmath>\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}</cmath> is <math>\boxed{\text{(C)\ 6.54}}</math>.  
~ le_petit_chouetteur from TSMV
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~Minor Formatting by GreenPlanet2050
 
~Minor Formatting by GreenPlanet2050
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==Video Solution by Math-X (MATH-X)==
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https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287
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~Math-X
  
 
==Video Solution (A Clever Explanation You’ll Get Instantly)==
 
==Video Solution (A Clever Explanation You’ll Get Instantly)==
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~Thesmartgreekmathdude
 
~Thesmartgreekmathdude
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==Video Solution by WhyMath==
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https://youtu.be/MasK0Z6wxR4
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{AMC8 box|year=2024|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 06:14, 15 November 2024

Problem 2

What is the value of this expression in decimal form? \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] $\textbf{(A) } 6.4\qquad\textbf{(B) } 6.504\qquad\textbf{(C) } 6.54\qquad\textbf{(D) } 6.9\qquad\textbf{(E) } 6.94$

Solution 1

We see that $\frac{44}{11}$ is $4$; $\frac{110}{44}$ simplifies to $\frac{5}{2}$, which is $2.5$;

and $\frac{44}{1100}$ simplifies to $\frac{1}{25}$, which is $0.04$;

$4+2.5+0.04$ reveals \[\frac{44}{11} + \frac{110}{44} + \frac{44}{1100}\] is $\boxed{\text{(C)\ 6.54}}$. ~

~Minor Formatting by GreenPlanet2050

Video Solution by Math-X (MATH-X)

https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287

~Math-X

Video Solution (A Clever Explanation You’ll Get Instantly)

https://youtu.be/5ZIFnqymdDQ?si=-FCGnA5WXQNp-JMF&t=175

~hsnacademy

Video Solution 1 (Quick and Easy!)

https://youtu.be/nzPT89ymlKk

~Education, the Study of Everything

Video Solution by Math-X (First understand the problem!!!)

https://youtu.be/BaE00H2SHQM?si=noTBPTosCtH31CpW&t=287

~Math-X

Video Solution by Daily Dose of Math (Understandable, Speedy, and Easy)

https://youtu.be/bSPWqeNO11M?si=HIzlxPjMfvGM5lxR

~Thesmartgreekmathdude

Video Solution by WhyMath

https://youtu.be/MasK0Z6wxR4

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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