Difference between revisions of "Vertical Angle Theorem"

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The '''Vertical Angle Theorem''' is a [[theorem]] that states that all [[vertical angles]] are congruent.
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The '''Vertical Angle Theorem''' is a [[theorem]] that states that all [[vertical Angles|vertical angles]] are congruent.
 
==Proof==
 
==Proof==
Assume all angle measures to be in [[radians]]. A pair of vertical angles are formed by [[line|lines]] <math>\overline A \overline B</math> and <math>\overline C \overline D</math> and the intersection of these lines is P. Angles <math>\angle APC</math> and <math>\angle BPD</math> are vertical angles. Let <math>m\angle APC = x</math>. From this, <math>m\angle CPB = \pi-x</math>, so $m\angle BPD = \pi-(\pi-x)=x=m\angle APC.
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Assume all angle measures to be in [[radians]]. A pair of vertical angles are formed by [[line|lines]] <math>\overline A \overline B</math> and <math>\overline C \overline D</math> and the intersection of these lines is P. Angles <math>\angle APC</math> and <math>\angle BPD</math> are vertical angles. Let <math>m \angle APC = x</math>. From this, <math>m\angle CPB = \pi-x</math>, so <math>m \angle BPD = \pi-(\pi-x)=x=m\angle APC.</math>
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Latest revision as of 21:10, 4 September 2024

The Vertical Angle Theorem is a theorem that states that all vertical angles are congruent.

Proof

Assume all angle measures to be in radians. A pair of vertical angles are formed by lines $\overline A \overline B$ and $\overline C \overline D$ and the intersection of these lines is P. Angles $\angle APC$ and $\angle BPD$ are vertical angles. Let $m \angle APC = x$. From this, $m\angle CPB = \pi-x$, so $m \angle BPD = \pi-(\pi-x)=x=m\angle APC.$

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