Difference between revisions of "User:Herefishyfishy1"

(New page: <math>i^n=cis(\frac{\pi n}{2})</math> <math>\forall a,b,c,n\in \mathbb{N}, n>2\Longrightarrow a^n+b^n\not=c^n</math>)
 
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<math>i^n=cis(\frac{\pi n}{2})</math>
 
  
<math>\forall a,b,c,n\in \mathbb{N}, n>2\Longrightarrow a^n+b^n\not=c^n</math>
 

Latest revision as of 09:14, 3 October 2009