Difference between revisions of "2000 AMC 10 Problems/Problem 14"
(New page: 71, 76, 80, 82, 91. The sum of the first 2 must be even, so we must choose 2 evens or the 2 odds. Let us look at the numbers (mod 3). 2,1,2,1,1. If we choose the two odds, the next num...) |
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− | + | #REDIRECT [[2000 AMC 12 Problems/Problem 9]] | |
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Latest revision as of 22:50, 26 November 2011
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