Difference between revisions of "2000 AMC 10 Problems/Problem 6"

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==Problem==
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#REDIRECT [[2000 AMC 12 Problems/Problem 4]]
 
 
==Solution==
 
 
 
The pattern of the units digits are
 
 
 
<math>1,1,2,3,5,8,3,1,4,5,9,4,3,7,0,7,7,4,1,5,6</math>
 
 
 
In order of appearance:
 
 
 
<math>1,2,3,5,8,4,9,7,0,6</math>.
 
 
 
<math>6</math> is the last.
 
 
 
<math>\boxed{\text{C}}</math>
 
 
 
==See Also==
 
 
 
{{AMC10 box|year=2000|num-b=5|num-a=7}}
 

Latest revision as of 22:34, 26 November 2011