Difference between revisions of "2000 AMC 10 Problems/Problem 12"

Latest revision as of 22:46, 26 November 2011

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-==Problem==
+#REDIRECT [[2000 AMC 12 Problems/Problem 8]]
-==Solution==
-We have a recursion:
-<math>A_n=A_{n-1}+4(n-1)</math>.
-I.E. we add increasing multiples of <math>4</math> each time we go up a figure.
-So, to go from Figure 0 to 100, we add
-<math>4 \cdot 1+4 \cdot 2+...+4 \cdot 99=4 \cdot 4950=19800</math>.
-<math>19801</math>
-B.
-==See Also==
-{{AMC10 box|year=2000|num-b=11|num-a=13}}