Difference between revisions of "1986 AJHSME Problems/Problem 3"

Latest revision as of 20:06, 3 July 2013

The smallest sum one could get by adding three different numbers from the set $\{ 7,25,-1,12,-3 \}$ is

$\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21$

To find the smallest sum, we just have to find the smallest 3 numbers and add them together.

Obviously, the numbers are $-3, -1, 7$ , and adding them gets us $3$ .

$\boxed{\text{C}}$

1986 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 2	Followed by Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

@@ Line 1: / Line 1: @@
 ==Problem==
-The smallest sum one could get by adding three different numbers from the set <math>\{ 7,25,-1,12,-3 \}</math> is
+The smallest [[sum]] one could get by adding three different numbers from the [[set]] <math>\{ 7,25,-1,12,-3 \}</math> is
 <math>\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21</math>
@@ Line 7: / Line 7: @@
 ==Solution==
-{{Solution}}
+To find the smallest sum, we just have to find the smallest 3 numbers and add them together.
+Obviously, the numbers are <math>-3, -1, 7</math>, and adding them gets us <math>3</math>.
+<math>\boxed{\text{C}}</math>
 ==See Also==
-[[1986 AJHSME Problems]]
+{{AJHSME box|year=1986|num-b=2|num-a=4}}
+[[Category:Introductory Algebra Problems]]
+{{MAA Notice}}