Difference between revisions of "2010 AMC 10B Problems/Problem 8"

Latest revision as of 19:36, 26 May 2020

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-We see how many common integer factors 48 and 64 share.
+#redirect [[2010 AMC 12B Problems/Problem 3]]
-Of the factors of 48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48; only 1, 2, 4, 8, and 16 are factors of 64.
-So there are <math>\boxed{\mathrm{(E)} 5}</math> possibilities for the ticket price.