Difference between revisions of "1968 IMO Problems/Problem 5"
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(b) <math>f(x) = 1</math> when <math>2n\le x < 2n+1</math> for some integer <math>n</math>, and <math>f(x)=\frac{1}{2}</math> when <math>2n+1\le x < 2n+2</math> for some integer <math>n</math>. | (b) <math>f(x) = 1</math> when <math>2n\le x < 2n+1</math> for some integer <math>n</math>, and <math>f(x)=\frac{1}{2}</math> when <math>2n+1\le x < 2n+2</math> for some integer <math>n</math>. | ||
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+ | == See Also == {{IMO box|year=1968|num-b=4|num-a=6}} | ||
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+ | [[Category:Olympiad Algebra Problems]] | ||
+ | [[Category:Functional Equation Problems]] |
Latest revision as of 12:33, 29 January 2021
Problem 5
Let be a real-valued function defined for all real numbers such that, for some positive constant , the equation holds for all .
(a) Prove that the function is periodic (i.e., there exists a positive number such that for all ).
(b) For , give an example of a non-constant function with the required properties.
Solution
(a) Since is true for any , and
We have: Therefore is periodic, with as a period.
(b) when for some integer , and when for some integer .
See Also
1968 IMO (Problems) • Resources | ||
Preceded by Problem 4 |
1 • 2 • 3 • 4 • 5 • 6 | Followed by Problem 6 |
All IMO Problems and Solutions |