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Difference between revisions of "2004 AMC 8 Problems/Problem 10"

(Created page with "==Problem== Handy Aaron helped a neighbor <math>1 \frac14</math> hours on Monday, <math>50</math> minutes on Tuesday, from 8:20 to 10:45 on Wednesday morning, and a half-hour on ...")
 
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==Solution==
 
==Solution==
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Convert everything to minutes and add them together. On Monday he worked for <math>\frac54 \cdot 60 = 75</math> minutes. On Tuesday he worked <math>50</math> minutes. On Wednesday he worked for <math>2</math> hours <math>25</math> minutes, or <math>2(60)+25=145</math> minutes. On Friday he worked <math>30</math> minutes. In total he worked for <math>75+50+145+30=300</math> minutes, or <math>300/60=5</math> hours and <math>5\cdot 3 = \boxed{\textbf{(E)}\ \textdollar 15}</math>.
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Let's convert everything to minutes and add them together. On Monday he worked for <math>\frac54 \cdot 60 = 75</math> minutes. On Tuesday he worked <math>50</math> minutes. On Wednesday he worked for <math>2</math> hours <math>25</math> minutes, or <math>2(60)+25=145</math> minutes. On Friday he worked <math>\frac{60}{2}=30</math> minutes. This adds up to <math>75+50+145+30=300</math> minutes, or <math>300/60=5</math> hours and <math>5\cdot 3 = \boxed{\textbf{(E)}\ \textdollar 15}</math>.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2004|num-b=9|num-a=11}}
 
{{AMC8 box|year=2004|num-b=9|num-a=11}}
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{{MAA Notice}}

Latest revision as of 01:09, 29 January 2023

Problem

Handy Aaron helped a neighbor $1 \frac14$ hours on Monday, $50$ minutes on Tuesday, from 8:20 to 10:45 on Wednesday morning, and a half-hour on Friday. He is paid $\textdollar 3$ per hour. How much did he earn for the week?

$\textbf{(A)}\ \textdollar 8 \qquad \textbf{(B)}\ \textdollar 9 \qquad \textbf{(C)}\ \textdollar 10 \qquad \textbf{(D)}\ \textdollar 12 \qquad \textbf{(E)}\ \textdollar 15$

Solution

Let's convert everything to minutes and add them together. On Monday he worked for $\frac54 \cdot 60 = 75$ minutes. On Tuesday he worked $50$ minutes. On Wednesday he worked for $2$ hours $25$ minutes, or $2(60)+25=145$ minutes. On Friday he worked $\frac{60}{2}=30$ minutes. This adds up to $75+50+145+30=300$ minutes, or $300/60=5$ hours and $5\cdot 3 = \boxed{\textbf{(E)}\ \textdollar 15}$.

See Also

2004 AMC 8 (Problems • Answer Key • Resources)
Preceded by
Problem 9 		Followed by
Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

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