Difference between revisions of "1951 AHSME Problems/Problem 34"
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Substitute <math>\log_{10}7=x</math> in <math> 10^{\log_{10}7} \Rightarrow 10^x=?</math> | Substitute <math>\log_{10}7=x</math> in <math> 10^{\log_{10}7} \Rightarrow 10^x=?</math> | ||
It was already stated that <math>10^x=7</math>, so our answer is <math> \textbf{(A)}\ 7</math> | It was already stated that <math>10^x=7</math>, so our answer is <math> \textbf{(A)}\ 7</math> | ||
| + | |||
| + | == See Also == | ||
| + | {{AHSME 50p box|year=1951|num-b=33|num-a=35}} | ||
| + | |||
| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 11:26, 5 July 2013
Problem
The value of 
is:
Solution
Substitute 
in 
It was already stated that 
, so our answer is 
See Also
| 1951 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 33 |
Followed by Problem 35 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
