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| − | ==Problem==
| + | #REDIRECT [[2013 AMC 12B Problems/Problem 1]] |
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| − | On a particular January day, the high temperature in Lincoln, Nebraska, was 16 degrees higher than the low temperature, and the average of the high and the low temperatures was <math>3\,^{\circ}\mathrm{}</math>. In degrees, what was the low temperature in Lincoln that day?
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| − | <math>\textbf{(A)}\ -13 \qquad\textbf{(B)}\ \-8 \qquad\textbf{(C)}\ \-5 \qquad\textbf{(D)}\ \-3 \qquad\textbf{(E)}\ \111</math>
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| − | ==Solution==
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| − | Let <math>L</math> be the low temperature. The high temperature is <math>L+16</math>. The average is <math>\frac{L+L+16}{2}=3</math>. Solving for <math>L</math>, we get <math>L=\boxed{\textbf{(C) } -5}</math>
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