Difference between revisions of "1962 AHSME Problems/Problem 33"
(Created page with "==Problem== The set of <math>x</math>-values satisfying the inequality <math>2 \leq |x-1| \leq 5</math> is: <math> \textbf{(A)}\ -4\leq x\leq-1\text{ or }3\leq x\leq 6\qquad</m...") |
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==Solution== | ==Solution== | ||
− | + | This inequality can be split into two inequalities: | |
+ | <math>2\le x-1\le5</math> or <math>2\le1-x\le5</math>. Solving for x gives | ||
+ | <math>3\le x\le6</math> or <math>-4\le x\le-1</math>. <math>\boxed{\textbf{(A)}}</math> |
Latest revision as of 17:45, 17 April 2014
Problem
The set of -values satisfying the inequality
is:
Solution
This inequality can be split into two inequalities:
or
. Solving for x gives
or
.