Difference between revisions of "1969 AHSME Problems/Problem 2"
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− | <math>\fbox{A}</math> | + | Let <math>c</math> be the cost. Selling the item for <math>x</math> dollars equates to losing <math>15\%</math> of <math>c</math>, so <math>x=.85c</math>. Selling the item for <math>y</math> dollars equates to profiting by <math>15\%</math> of <math>c</math>, so <math>y=1.15c</math>. Therefore <math>\frac{y}{x}=\frac{1.15c}{.85c}=\frac{23}{17}</math>. The answer is <math>\fbox{A}</math>. |
== See also == | == See also == |
Latest revision as of 18:27, 10 July 2015
Problem
If an item is sold for dollars, there is a loss of based on the cost. If, however, the same item is sold for dollars, there is a profit of based on the cost. The ratio of is:
Solution
Let be the cost. Selling the item for dollars equates to losing of , so . Selling the item for dollars equates to profiting by of , so . Therefore . The answer is .
See also
1969 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
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All AHSME Problems and Solutions |
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