Difference between revisions of "1969 AHSME Problems/Problem 31"
(Created page with "== Problem == Let <math>OABC</math> be a unit square in the <math>xy</math>-plane with <math>O(0,0),A(1,0),B(1,1)</math> and <math>C(0,1)</math>. Let <math>u=x^2-y^2</math>, and ...") |
Rockmanex3 (talk | contribs) (Solution to Problem 31 — weird graphing translation) |
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</asy> | </asy> | ||
+ | |||
+ | <asy> | ||
+ | draw((-3,0)--(3,0),EndArrow); | ||
+ | draw((0,-4)--(0,4),EndArrow); | ||
+ | draw((-1,0)--(0,1)--(1,0)--(0,-1)--cycle,dot); | ||
+ | MP("(E)",(-5,2),SW); | ||
+ | MP("O",(.1,.1),SW); | ||
+ | MP("(-1,0)",(-1,0),SW); | ||
+ | MP("(0,1)",(0,1),NE); | ||
+ | MP("(1,0)",(1,0),SE); | ||
+ | MP("(0,-1)",(0,-1),SE); | ||
+ | </asy> | ||
== Solution == | == Solution == | ||
− | <math>\ | + | Each point on the square can be in the form <math>(0,y)</math>, <math>(1,y)</math>, <math>(x,0)</math>, and <math>(x,1)</math>, where <math>0 \le x,y \le 1</math>. Making the appropriate substitutions results in points being <math>(-y^2,0)</math>, <math>(1-y^2,2y)</math>, <math>(x^2,0)</math>, and <math>(x^2 - 1,2x)</math> on the <math>uv</math>-plane. |
+ | |||
+ | Notice that since <math>v \ge 0</math>, none of the points are below the u-axis, so options A,B, and E are out. Since <math>x = \tfrac{v}{2}</math>, <math>u = (\tfrac{v}{2})^2 - 1</math>, so <math>v = 2\sqrt{u+1}</math>, where <math>-1 \le u \le 0</math>. That means some of the lines are not straight, so the answer is <math>\boxed{\textbf{(D)}}</math>. | ||
− | == See | + | == See Also == |
{{AHSME 35p box|year=1969|num-b=30|num-a=32}} | {{AHSME 35p box|year=1969|num-b=30|num-a=32}} | ||
− | [[Category: Intermediate | + | [[Category: Intermediate Algebra Problems]] |
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 16:24, 20 June 2018
Problem
Let be a unit square in the -plane with and . Let , and be a transformation of the -plane into the -plane. The transform (or image) of the square is:
Solution
Each point on the square can be in the form , , , and , where . Making the appropriate substitutions results in points being , , , and on the -plane.
Notice that since , none of the points are below the u-axis, so options A,B, and E are out. Since , , so , where . That means some of the lines are not straight, so the answer is .
See Also
1969 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 30 |
Followed by Problem 32 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.