Difference between revisions of "1981 AHSME Problems/Problem 1"
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− | If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals: | + | ==Problem== |
+ | If <math>\sqrt{x+2}=2</math>, then <math> (x+2)^2 </math> equals: | ||
+ | |||
<math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math> | <math> \textbf{(A)}\ \sqrt{2}\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 4\qquad\textbf{(D)}\ 8\qquad\textbf{(E)}\ 16 </math> | ||
+ | |||
+ | |||
+ | ==Solution 1== | ||
+ | If we square both sides of the <math>\sqrt{x+2} = 2</math>, we will get <math>x+2 = 4</math>, if we square that again, we get <math>(x+2)^2 = \boxed{\textbf{(E) }16}</math> | ||
+ | |||
+ | ==Solution 2== | ||
+ | We can immediately get that <math>x = 2</math>, after we square <math>(2+2)</math>, we get <math>\boxed{\textbf{(E) }16}</math> |
Latest revision as of 01:26, 15 January 2020
Problem
If , then
equals:
Solution 1
If we square both sides of the , we will get
, if we square that again, we get
Solution 2
We can immediately get that , after we square
, we get